XF 2.0 How to detect if a user ($user) is Super Moderator?

[Scandal]

Well, for admin we have $user->is_admin
For super admin we have $user->is_super_admin
There is also the general $user->is_moderator

Is there any similar way to determine if a $user is Super Moderator?
Or any suggestion how to detect it with no extra queries?

 

[Jeremy P]

I don't believe there is any way to do this in the core. You could add a relation between the User entity and the Moderator entity, and then use $user->Moderator->is_super_moderator, but this will incur an additional query unless you can eager-load the Moderator relation everywhere you need it.

It's worth noting that is_super_admin works the same way (it will incur an additional query unless the Admin relation is eager-loaded), though it uses a getter that first checks the is_admin column, which will mitigate this somewhat.

 

[Scandal]

Thanks Jeremy, I used a relation via the Finder so it is doing just a mysql join, so no extra query

 

[HappyWorld]

I think it is easier if you assign all super moderator to a unique usergroup (secondary usergroup), and you can check if a user is member of that usergroup

 

[TobiasHartlehnert]

Don't know which version introduced this, but at least with v2.3.6+ you can use

$xf.visitor->is_super_moderator

in templates.