XF 2.1 How to access style id from template? $xf.style.id does'nt work

[Earl]

{{ dump($xf) }} shows this:

{{ dump($xf.style) }} shows this:

but {{ dump($xf.style.id) }} shows null:

I'm confused

 

[Chris D]

Dumping an object in this way isn't always the best way to reveal the methods and properties it has.

The reason this doesn't work is id is actually a protected property (I think that's what the # means, in fact).

But something that is useful here is that it tells you that style is actually a Style object and if you're unsure of what the full class name is you can hover over the word Style. In this case it is XF\Style.

If you take a look at that class, hopefully it will become clear how to access the style ID.

 

[Earl]

Dumping an object in this way isn't always the best way to reveal the methods and properties it has.

The reason this doesn't work is id is actually a protected property (I think that's what the # means, in fact).

But something that is useful here is that it tells you that style is actually a Style object and if you're unsure of what the full class name is you can hover over the word Style. In this case it is XF\Style.

If you take a look at that class, hopefully it will become clear how to access the style ID.

Thank you for giving very informative response. I found how to access it with the help of your reply ($xf.style.style_id).