$today = date("m.d.y"); // 03.10.01
Although interestingly, it lists "d" as 2 digits with leading zeros, which your example doesn't have.
What won't work? We return a localized version of date('F j'), so it will respond to translation - where's the serious limitation there?Sorry, but this won't work in many parts of the world and in 2011 we call this a bug![]()
so it will respond to translation
It's just the internal reference for "birthday" date types. You can explicitly override the type in the template, if it's that significant.Can you explain this part, please? (Is there a phrase "F j" which I can change to "d. F"?)
You can explicitly override the type in the template
We use essential cookies to make this site work, and optional cookies to enhance your experience.