xf_user cookie issue

[liv4spd]

I am trying to use xf_user cookie to display different information depending on whether a user is logged on or not. Below is the code, I am thinking to use.

The problem is that when users are not logged in, xf_user is not definied, so I am getting a ton of the below error messages in my error log.
"undefinied index: xf_user".

Any idea, how I can get over this?

Thank you!

$bbuserid = $_COOKIE["xf_user"];

if ($bbuserid != '') {
// display information for users who are logged on:
......
}

if ($bbuserid == '') {
// display information for users who are not logged on:
......
}

 

[AndyB]

I assume this is in an add-on, in that case the thread should have been started in this forum:

http://xenforo.com/community/forums/xenforo-development-discussions.34/

Try this:

$bbuserid = $_COOKIE["xf_user"];

if ($bbuserid) {
// display information for users who are logged on:
......
}

if (!$bbuserid) {
// display information for users who are not logged on:
......
}

 

[Jake Bunce]

$bbuserid = (isset($_COOKIE["xf_user"]) ? $_COOKIE["xf_user"] : '');

if ($bbuserid != '') {
// display information for users who are logged on:
......
}

if ($bbuserid == '') {
// display information for users who are not logged on:
......
}

That will fix the error message.

 

[liv4spd]

It works! Now my website is clear of errors

I appreciate the big help very much.

$bbuserid = (isset($_COOKIE["xf_user"]) ? $_COOKIE["xf_user"] : '');

if ($bbuserid != '') {
// display information for users who are logged on:
......
}

if ($bbuserid == '') {
// display information for users who are not logged on:
......
}

That will fix the error message.