XF 2.1 Random phrase in PHP

[Ozzy47]

In my PHP file I have this bit of code:

            if ($spamcheck == '')
            {
                return $this->error(\XF::phrase('did_not_complete_the_captcha_verification_properly'));
            }

This works as intended. Now what I would like to do is use a random phrase from a list, how would I acheive that?

 

[Paul B]

Use the PHP rand function and if statements.

 

[Ozzy47]

Have a working example?

 

[Chris D]

if ($spamcheck == '')
{
    $phrases = [
        'did_not_complete_the_captcha_verification_properly',
        'another_phrase',
        'some_other_phrase',
        'yet_another_phrase'
    ];
    $key = array_rand($phrases);
    return $this->error(\XF::phrase($phrases[$key]));
}

PHP: array_rand - Manual

PHP is a popular general-purpose scripting language that powers everything from your blog to the most popular websites in the world.

php.net

 

[Ozzy47]

if ($spamcheck == '')
{
    $phrases = [
        'did_not_complete_the_captcha_verification_properly',
        'another_phrase',
        'some_other_phrase',
        'yet_another_phrase'
    ];
    $key = array_rand($phrases);
    return $this->error(\XF::phrase($phrases[$key]));
}

PHP: array_rand - Manual

PHP is a popular general-purpose scripting language that powers everything from your blog to the most popular websites in the world.

php.net

Perfect, I see now what I was missing when I tried, and I also did not get the return right.