XF 2.2 Which condition for display widget only in forum_list template ?

[Deleted member 184953]

Hello,

As title, i've searched without success...
(because i put the widget in footer, so...)

Thanks !

 

[Deleted member 184953]

Ok, i used conditional directly on PAGE_CONTAINER.
But if someone know the conditional syntax to write in the conditional field in widget parameters... Thanks !

 

[Ozzy47]

Why not just use one of the forum list display locations?

 

[Ozzy47]

$xf.reply.template == 'forum_list'

 

[Deleted member 184953]

Why not just use one of the forum list display locations?

Hello, because i wanted to display this custom HTML widget inside the footer and only on forum_list.

 

[Deleted member 184953]

$xf.reply.template == 'forum_list'

Perfect ! many many thanks !

 

[Ozzy47]

Not a problem, glad to help.