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We employ quite a number of User Groups as most of our Nodes are Private and we setup User Groups to control access to these private Nodes. We typically name the user group with the same name as the node. So, for example Node = "Private Forum 1" has a correspondening User Group called "Private Forum 1". Hence, adding a user to the User Group = "Private Forum 1" gives that user access to the private node = "Private Forum 1"
The issue is that Nodes are sorted manually, via the hierarchy/order we create. On the other hand, User Groups are listed alphabetically, and can't be manually sorted. The end result is that the User Groups are in a different order than our Nodes. This would not be an issue other than we now have quite a few User Groups & Nodes on our forum.
So, when hoping to give a new user access to various private nodes, we must go through the User Group list, which is in a different order than the node list. This becomes confusing given the quantity we have.
So, my question is, is there any way to manually sort the User Group list so that it is organized in the same manner as our Node list? I guess I could develop a naming convention in our User Group list so that I can force this match-up, but I'm wonder if there is a simplier way.
Any thoughts?
The issue is that Nodes are sorted manually, via the hierarchy/order we create. On the other hand, User Groups are listed alphabetically, and can't be manually sorted. The end result is that the User Groups are in a different order than our Nodes. This would not be an issue other than we now have quite a few User Groups & Nodes on our forum.
So, when hoping to give a new user access to various private nodes, we must go through the User Group list, which is in a different order than the node list. This becomes confusing given the quantity we have.
So, my question is, is there any way to manually sort the User Group list so that it is organized in the same manner as our Node list? I guess I could develop a naming convention in our User Group list so that I can force this match-up, but I'm wonder if there is a simplier way.
Any thoughts?