XF 2.1 conditional statement, how to

[Deleted member 184953]

Hello,

How to write this more code compliant ?

        <xf:if is="$xf.visitor.user_id">
        <xf:if is="$template == 'forum_list'">
              ...
        </xf:if>
        </xf:if>

Thanks

 

[SyTry]

Hello,

How to write this more code compliant ?

        <xf:if is="$xf.visitor.user_id">
        <xf:if is="$template == 'forum_list'">
              ...
        </xf:if>
        </xf:if>

Thanks

Hello,

Did you try this :

<xf:if is="$xf.visitor.user_id AND $template == 'forum_list'">
    You code here
</xf:if>

Doc :

Template syntax | Developer Documentation | XenForo

Developer documentation for XenForo

xenforo.com

Regards, SyTry