J James Well-known member Jul 22, 2011 #1 Just curious - will it be there?! (Question aimed at XF devs - obviously)
Paul B XenForo moderator Staff member Jul 22, 2011 #3 Do you mean like this? <xen:if is="!{xen:helper ismemberof, $visitor, 3} AND !{xen:helper ismemberof, $visitor, 4}"> Or do you mean as an array?
Do you mean like this? <xen:if is="!{xen:helper ismemberof, $visitor, 3} AND !{xen:helper ismemberof, $visitor, 4}"> Or do you mean as an array?
J James Well-known member Jul 22, 2011 #4 Brogan said: Do you mean like this? <xen:if is="!{xen:helper ismemberof, $visitor, 3} AND !{xen:helper ismemberof, $visitor, 4}"> Or do you mean as an array? Click to expand... Like this: <xen:if is="{xen:helper ismemberof, $visitor, 3, 4, 5,}"> Where 3,4,5 represent IDs. Of course, that's the vB approach and they may choose something like: <xen:if is="{xen:helper ismemberof, $visitor, {xen:array 3,4,5}}">
Brogan said: Do you mean like this? <xen:if is="!{xen:helper ismemberof, $visitor, 3} AND !{xen:helper ismemberof, $visitor, 4}"> Or do you mean as an array? Click to expand... Like this: <xen:if is="{xen:helper ismemberof, $visitor, 3, 4, 5,}"> Where 3,4,5 represent IDs. Of course, that's the vB approach and they may choose something like: <xen:if is="{xen:helper ismemberof, $visitor, {xen:array 3,4,5}}">
Kier XenForo developer Staff member Jul 22, 2011 #5 The xen:array syntax is a little ugly in that instance, I'd prefer to have {xen:helper ismemberof, $user, 2, 3, 4, 5} I think.
The xen:array syntax is a little ugly in that instance, I'd prefer to have {xen:helper ismemberof, $user, 2, 3, 4, 5} I think.
Paul B XenForo moderator Staff member Jul 27, 2011 #8 Will the old method continue to work alongside?
Kier XenForo developer Staff member Jul 27, 2011 #9 Yes, it's fully backward compatible. Old: {xen:helper ismemberof, $user, $userGroupId} New: {xen:helper ismemberof, $user, $userGroupId1, $userGroupId2, ... $userGroupIdx}
Yes, it's fully backward compatible. Old: {xen:helper ismemberof, $user, $userGroupId} New: {xen:helper ismemberof, $user, $userGroupId1, $userGroupId2, ... $userGroupIdx}