XF 2.1 Short conditional inside template (modification)

[Scandal]

Well, we have this part from template "forum_post_thread":

<xf:submitrow submit="{{ phrase('post_thread') }}" icon="write" sticky="true">

I try to create a template modification to apply an "onclick" event on that submit button.

This is what I fill on the fields:
Search:

icon="write"

Replace:

$0 {{ ( $xf.request.filter('myvar', 'int') == 1 ? "onclick="alert('{{ phrase('phrase_name') }}');"" : '') }}

... but it returns syntax error.
I can't apply full conditional <xf:if> cause <xf:submitrow> is not allow inside it. I could apply as "Search" the whole submitrow field and then use <xf:if>, but I don't want too so it can be more compatible with future xF versions.

I suppose that the issue is on the " and ' characters but don't know how to fix it. I tried too some escape \ characters with no result.

Any idea?

 

[Jeremy P]

In XF, there are other facilities to apply click handlers to elements (namely XF.Event JS handlers). Nevertheless, you can make this work using the replacement:

$0 onclick="{{ $xf.request.filter('myvar', 'int') == 1 ? 'alert(\'' . phrase('phrase_name') . '\');' : '' }}"

You generally want to put conditionals inside attributes, you have to escape nested quotes, and you should use concatenation instead of nesting {{ ... }} expressions.

 

[Scandal]

Thank you very much!