So, I have my last three exams next week (2xFurther Maths, Chemistry C3), then it's the leavers assembly on the Monday after that (23rd), then the prom (which I'm being forced to go to) on the Thursday (26th). Then I've got a Year 11 day on 30th (Monday, I believe), and then I'm free... 18 days before everyone else breaks up for summer. That's gonna feel strange... Any how, just posting this, because, to be honest, I am currently incredibly bored! I want to go out, but I know there's no point in going out if I don't have any money For fun, I've left a further maths question attached... Answer it and the well done's will be with you (I'm sure it isn't hard). Liam

Good luck Liam, have my final two today ... javascript and WHS. Might call for a massive alcohol refurbishment this evening to get over it all

Line PC is perpendicular, so the gradient is 0.5. Given that m = 0.5 (I'll use this instead of 1/2), the equation of line follows the notion that y = 0.5x + c. Substitute x1 = 4 and y1 = 5 into the y1-y2 = x1-x2 gives you y-5 = 0.5(x-4) => y-5 = 0.5x - 2 => y = 0.5x + 3. The value of c is 3. At the centre, where x=0, substitute x = 0 into y=0.5x + 3, y=0.5(0) + 3, therefore y = 3. Using x^2 + y^2 = r^2, (5-3)^2 + (4+0)^2. or 2^2 + 4^2 = 20^2 Radius is thus sqrt(20). (I have no idea if this is correct), I don't recall that much for school maths. Thus, (y-3)^2 + x^2= 20.

All the ", then "s reminded me of the dude where's my car scene when they're ordering food. Congrats on being onto summer. Don't be so negative about prom, lots of people tend to "get lucky". Play your cards right and maybe spike the punch (Jk don't do that ).