XF 2.1 How to add new PHP conditional if certain domain is used?

[rdn]

So I have this code from an addon (coded by @TickTackk 2 years ago I think).

if ((!$visitor->user_id || $visitor->user_state !== 'valid') && !$this->internalRenderedLink && $linkInfo['type'] !== 'internal')

From what I understand, skip if the visitors is not logged or not valid and also if internal links.

I want to add more condition, if the domain is equal to google.com then skip the condition.
What would be the exact code to use?

Many Thanks!

 

[Lukas W.]

The provided snippet is not large enough to give you any code samples that could work. We don't even know what variable the URL is stored in.

 

[rdn]

Thanks, this is the whole Code.

<?php

namespace TickTackk\HideLinksFromGuest\XF\BbCode\Renderer;

/**
 * Class Html
 *
 * @package TickTackk\HideLinksFromGuest\XF\BbCode\Renderer
 */
class Html extends XFCP_Html
{
    /**
     * @var null|bool
     */
    protected $internalRenderedLink;

    /**
     * @param string $text
     * @param string $url
     * @param array  $options
     *
     * @return string|\XF\Phrase
     */
    protected function getRenderedLink($text, $url, array $options)
    {
        $linkInfo = $this->formatter->getLinkClassTarget($url);
        $visitor = \XF::visitor();
        if ((!$visitor->user_id || $visitor->user_state !== 'valid') && !$this->internalRenderedLink && $linkInfo['type'] !== 'internal')
        {
            $router = \XF::app()->router('public');
            $this->internalRenderedLink = true;
            try
            {
                return \XF::phrase('tckHideLinksFromGuest_you_must_x_or_y_to_view_this_link', [
                    'register_link' => $this->getRenderedLink(\XF::phrase('tckHideLinksFromGuest_register'), $router->buildLink('register'), []),
                    'login_link' => $this->getRenderedLink(\XF::phrase('tckHideLinksFromGuest_login'), $router->buildLink('login'), [])
                ])->render('raw');
            }
            finally
            {
                $this->internalRenderedLink = false;
            }
        }

        return parent::getRenderedLink($text, $url, $options);
    }
}

 

[Jeremy P]

I think you'd have to parse the URL to get this information:

$host = parse_url($url, PHP_URL_HOST);

This will give the full host, including any subdomains. To match sub-domains too you'd need to use a regular expression:

if (preg_match('#(^|\.)google\.com$#i', $host)) {
    // ...
}