XF 2.1 how to disable/enable a widget only for one style

[🔥Iggy🔥]

hello,
can anyone explain this to me please?

specifically need to hide the media gallery slider for one style.....i thought it should be an easy fix by css at least but the solution escaped me...then of course i got wondering about proper solutions

thank you

 

[Paul B]

You can set the widget to have no position and manually call it in the templates using:

<xf:widget key="widget_key" />

So the reverse of what you are trying to do, but the result will be the same.

 

[🔥Iggy🔥]

hmm...where would i put it in which template exactly....i am going for "forum list:above nodes"

also i was wondering perhaps something in the display conditions option might be better?
not sure how that would be phrased exactly but something like if style id15, style id 16, etc or such?

 

[Ozzy47]

{$xf.visitor.style_id} == 1

 

[Paul B]

Something like this should work:

{$xf.visitor.style_id} != 1

Change the 1 to the style you don't want it to display in.

 

[🔥Iggy🔥]

thanks you all i appreciate that....

photo finish on the solution tho um hmm
its a tie!
thank you tho seriously..

 

[Paul B]

Each statement does opposite things - Ozzy's will show it in only one style, mine will prevent it showing in only one style.

 

[🔥Iggy🔥]

its good to know both, we have sort of alot of styles so its better for us to prevent the one....but maybe another time the other will be better

 

[Paul B]

Yes, based on your original request, that's why I posted the statement I did.

specifically need to hide the media gallery slider for one style

 

[🔥Iggy🔥]

true but the second time i reversed it, still a tie

 

[Hoerspiel]

Something like this should work:

{$xf.visitor.style_id} != 1

Change the 1 to the style you don't want it to display in.

Is it possible two use this for more then one style? For example something like

{$xf.visitor.style_id} != 1, 2 or {$xf.visitor.style_id} != 1 AND 2

Many styles have dark and light themes, this would make it easier.

 

[Paul B]

<xf:if is="!in_array($xf.visitor.style_id, [1, 2, 3])">